Balance the following chemical equations with examples. and explain about coefficient of reaction.

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What is chemical reaction?

A chemical reaction is a reaction in which the chemical transformation of one set of chemical substance to another. it is given in the form of chemical substance. this is known as chemical reaction.

for examples :-

balance the following chemical equation

Balance the following chemical equation: –

(a) HNO3 + Ca(OH)2 – Ca(NO3)2 + H2O

(b) NaOH + H2SO4 – Na2SO4 + H2O

(c) NaCl + AgNO3 – Agcl + NaNo3

(d) Bacl2 + H2SO4 – BaSO4 + HCl

(a) HNO3 + Ca (OH)2 – Ca (NO3)2 + H2O

Balance equation :-

2HNO3 + Ca (OH)2 – Ca (NO3)2 + 2H2O

If we are talking about coefficient of this reaction. how we can calculate the value of coefficient for HNO3 and H2O molecules.

Coefficient – number in front of variable,

for example :-

balanced equation

therefore, we can say that,

the coefficient of HNO3 is – 2

the coefficient of H2O is – 2

(b) NaOH + H2SO4 – Na2SO4 + H2O

Balance equation :-

2NaOH + H2SO4 – Na2SO4 + 2H2O

And the coefficient of NaOH is 2, and the coefficient of H2O is 2.

(c) NaCl + AgNO3 – Agcl + NaNo3

Balance equation :-

NaCl + AgNO3 – Agcl + NaNo3

there is no any coefficient available in this reaction.

(d) Bacl2 + H2SO4 – BaSO4 + HCl

Balance equation :-

Bacl2 + H2SO4 – BaSO4 + 2HCl

According to this reaction, we can say thet the coefficient of HCl is 2.

How to balance a chemical equation by hit and trial method?

This method is use for balancing simple chemical equations and consists in counting up the number atoms of each element on both sides and trying to equalize them. according to this we can balance a chemical equation.

let’s know with example

The atoms which occur at minimum number of places on both sides should be selected first and one occurring maximum number of times should be taken last of all.

For example :

balancing the equation

first of all, in this equation, the order of selection should be Na, O, H.

(a) there are one sodium atom on both sides, hence it does not require any further equalizing.

(b) same is the case of oxygen.

(c) there are even number of hydrogen atoms on the L. H. S being 2, and odd number of these on R. H. S. being 3. and also multiply naoh by 2. This make the total number of hydrogen atoms on R. H. S. equal to 4. Multiply H2O on L.H.S. by 2 to equalize hydrogen atoms and Na by 2 to equalize sodium atoms. According to this methods, the balanced equation of this equation is,

balance the following chemical equation

According to this methods, this way, we can find balanced chemical equation.


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